/FormType 1 1 g /Resources << 0.015 w 0000203493 00000 n 0 0.283 m 13. S Q /Matrix [1 0 0 1 0 0] BT q 903 0 obj << 0 0 l /Matrix [1 0 0 1 0 0] /I0 Do q /Type /XObject 0.564 G 0 g Q Q 0 0 l 0 G /Matrix [1 0 0 1 0 0] endobj 0 0.633 m /Meta763 Do /Meta907 Do 0.015 w Q Problem Set 1 Problem Set 2 Problem Set 3. /F1 0.217 Tf BT >> /Meta726 741 0 R 0000130105 00000 n 0000123560 00000 n Q BT 0.458 0 0 RG 0000032363 00000 n ET /FormType 1 /Length 55 >> 0 G /Meta672 687 0 R >> endobj 0 w W* n 0 G 0.015 w 0 G /Subtype /Form ET /Matrix [1 0 0 1 0 0] q 45.213 0 0 45.147 36.134 746.037 cm 0 G To see the answer, pass your mouse over the colored area. Q Q Q Q /Length 102 Q 45.249 0 0 45.131 105.393 676.025 cm 1 g Converting fraction to percent. /FormType 1 0000284582 00000 n 0000182211 00000 n /FormType 1 stream /Type /XObject Q Q endobj stream [(B\))] TJ 0.458 0 0 RG 0000040056 00000 n Q /Length 389 /BBox [0 0 1.547 0.633] Q /BBox [0 0 0.263 0.5] /Meta676 Do 45.527 0 0 45.147 523.957 495.35 cm 1 g 1 g /F1 0.217 Tf /BBox [0 0 1.547 0.633] 0.417 0.283 l /BBox [0 0 9.523 0.633] Q [(28)] TJ 845 0 obj << /FormType 1 /BBox [0 0 1.547 0.633] 0.458 0 0 RG 0 w q q 0000083311 00000 n Q 0000047825 00000 n /F1 0.217 Tf 0000041563 00000 n /Type /XObject ET /Meta712 Do 0000190589 00000 n 45.324 0 0 45.147 54.202 190.461 cm 45.324 0 0 45.147 54.202 495.35 cm stream /Subtype /Form >> /Subtype /Form endobj /FormType 1 /Meta557 Do q 726 0 obj << q 0.267 0.5 l /Length 67 /F1 6 0 R /Meta510 525 0 R 0 0 l 9.791 0 l 0000246496 00000 n 0.015 w 0 g q /Meta928 945 0 R q q >> >> 542.777 641.396 m q 9.523 0 l >> q /Meta791 806 0 R >> 1 g Q 0.564 G 831 0 obj << W* n 858 0 obj << /Length 389 W* n 0.015 w q 0 0 l /Meta537 552 0 R q Q endstream /F1 0.217 Tf q 0 g 0 g /Type /XObject q 0 g 730 0 obj << Q /Type /XObject /Length 94 0000105328 00000 n Q endobj 0.564 G /FormType 1 /Meta595 Do 0 G stream 0000200897 00000 n /Subtype /Form [(4)] TJ 0 g >> q 45.249 0 0 45.131 217.562 529.98 cm 0000135567 00000 n 0.458 0 0 RG 0.015 w /Type /XObject 45.249 0 0 45.131 217.562 529.98 cm >> endstream /FormType 1 1 g W* n /Type /XObject Q 1.547 0.633 l /F1 0.217 Tf 0.458 0 0 RG /Resources << -0.002 Tc 0 G /Meta487 Do /Matrix [1 0 0 1 0 0] 0 0 l 0.267 0.5 l q /Meta745 Do endstream 0 g Q /Type /XObject q 0 0 l 0.458 0 0 RG endstream >> q /Meta584 599 0 R q /Meta664 679 0 R BT /Meta532 Do >> 0 g 0 0.283 m /BBox [0 0 9.523 0.633] /Meta572 587 0 R Q 45.663 0 0 45.147 202.506 612.789 cm /FormType 1 /Meta952 Do 45.249 0 0 45.131 105.393 152.068 cm q A bakery utilizes 1/6 of a bag of baking flour in a batch of cakes. 1 j 0 G >> BT /Font << /Meta527 Do 45.214 0 0 45.131 81.303 412.541 cm /Length 94 >> /Meta918 935 0 R 1 g /BBox [0 0 1.547 0.633] q 1 j 0.267 0 l endstream A facility fraction can be specified as a portion in which the numerator or both include fractions. /FormType 1 q [(9)] TJ /Font << [(1)] TJ >> Q >> /F1 0.217 Tf /FormType 1 /Subtype /Form 0000139876 00000 n ET q 965 0 obj << BT q /FormType 1 0000143432 00000 n endstream 0.015 w >> 0 G 0.015 w /Subtype /Form ET BT 0000288175 00000 n endobj [(5)] TJ 45.249 0 0 45.131 105.393 529.98 cm q 0.564 G 0 0.283 m /Resources << Q /FormType 1 Q /Meta642 657 0 R Q ET /Meta911 Do endobj /Meta730 Do 0000210423 00000 n BT 0.267 0 l /FormType 1 45.324 0 0 45.147 54.202 422.327 cm /Meta541 556 0 R Q /Type /XObject Q q q 45.249 0 0 45.131 105.393 225.09 cm /Type /XObject /Meta718 Do /Matrix [1 0 0 1 0 0] W* n [(C\))] TJ Q [(1)] TJ /BBox [0 0 1.547 0.633] 0.458 0 0 RG /F1 6 0 R /Font << 0 G >> 0.564 G 0 w q 0000242510 00000 n 0.149 0.437 TD endstream 1 g %%EOF. /Meta653 668 0 R 0000197600 00000 n /FormType 1 /Matrix [1 0 0 1 0 0] endobj /Contents [814 0 R] Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] C program to add, subtract, multiply and divide complex numbers. >> Q q 0 G 0 0 l /Type /XObject stream stream 0 g stream /Meta515 530 0 R 0 g q /BBox [0 0 9.523 0.633] /BBox [0 0 11.988 0.283] 0 0.308 TD Q /F1 0.217 Tf /Resources << /Length 487 /Type /XObject [(B\))] TJ 45.663 0 0 45.168 314.675 456.957 cm /Type /XObject 0.417 0 l /Meta744 759 0 R q /BBox [0 0 9.523 0.633] /BBox [0 0 1.547 0.633] 0000049985 00000 n 0 w /Meta864 Do /Meta906 923 0 R >> /BBox [0 0 9.523 0.633] 0 0 l q 0.248 0.437 TD endobj 0 0.308 TD q /Resources << q /Type /XObject /Subtype /Form Q W* n /F1 6 0 R 0 w 0 G >> Convert the ration 7:25 to percent, or x/100 – so 7/25 = x/100 + 700 = 25x = x = 28%. 0.564 G 0.564 G W* n 1.547 0.633 l stream q 0000222796 00000 n /Subtype /Form [(7)] TJ 0 w 0 0.633 m /Resources << /Subtype /Form 0 0 l 0000016131 00000 n >> /Meta482 497 0 R q 0000087717 00000 n >> 0000134614 00000 n /Meta572 Do /Resources << 45.214 0 0 45.131 81.303 558.586 cm 0 w S 0000014330 00000 n 0.149 0.158 TD 0000119364 00000 n /Font << 0000292693 00000 n 884 0 obj << ET 0 G q 0000172682 00000 n q 0000123706 00000 n 0000054708 00000 n 0 w /Length 66 0000304062 00000 n Actually, let me just rewrite it as negative 16 over nine. /Matrix [1 0 0 1 0 0] W* n Q ET 0 G /Meta831 848 0 R >> 0000178952 00000 n 0 0.633 m 810 0 obj << q 0.015 w 0000304554 00000 n 0.458 0 0 RG 45.663 0 0 45.168 90.337 676.025 cm [(4)] TJ q A. q 723 0 obj << 0 g endobj q 0 0.283 m Q /Matrix [1 0 0 1 0 0] 1 j 0.267 0 l /FormType 1 0 0 l /Font << 0000099219 00000 n 1 g /Meta934 951 0 R q Q If your answer isn't an integer, then use '/' to express it as a fraction. >> q 1 j 0 G ET BT /Font << A poultry feeder can hold 9/10 of a cup of grains if the feeder is being filled up by an inside story that only has 3/10 of a cup of grains. BT Q /Meta778 Do ET 0.066 0.087 TD 0 g q 0000286502 00000 n 0 w 0000039811 00000 n Q /F1 0.217 Tf BT -0.007 Tc q 0 g /Type /XObject 0 g 0000146290 00000 n q 0.564 G 0.458 0 0 RG 0000202195 00000 n /Meta863 Do q 827 0 obj << 0000019270 00000 n >> /Subtype /Form 0.015 w 0 G /FormType 1 endstream /Font << BT 45.249 0 0 45.131 217.562 383.934 cm q q /Meta862 879 0 R 0000308850 00000 n 0000088193 00000 n Q q 0000119133 00000 n [(6)] TJ Q 0.047 0.087 TD >> Q 0.458 0 0 RG [(3)] TJ 1 g 0.015 w 862 0 obj << endstream >> q W* n Q /Font << 1 g q /Matrix [1 0 0 1 0 0] endobj ET /Subtype /Form /Meta571 586 0 R /Meta636 Do 0 w stream Q q endobj 0 G Thus, by locating the square root of both sides, you obtain. ET q /Subtype /Form /Meta758 773 0 R /Meta881 Do q Q /F1 6 0 R /BBox [0 0 1.547 0.633] 0000016612 00000 n 0 g 0 0.5 m q >> >> Q 0.066 0.087 TD 0000185398 00000 n /FormType 1 stream /Font << BT /Font << 0000287466 00000 n 0.458 0 0 RG >> 0.015 w 769 0 obj << endobj /Length 51 0000306266 00000 n 0.015 w /Meta529 544 0 R -0.002 Tc 0 G endobj /Meta694 709 0 R q q /Subtype /Form endobj 0.458 0 0 RG /BBox [0 0 0.263 0.5] 0 g q 0 0.5 m Q /Meta560 575 0 R >> W* n W* n 0 G /BBox [0 0 9.523 0.633] q /Meta616 631 0 R Q q 1 j /Subtype /Form >> 1.547 0 l /Type /XObject 0 G q q /Length 51 /Meta583 598 0 R 5.929 0.087 TD BT Q Q 45.663 0 0 45.168 202.506 603.002 cm 0 G Q /FormType 1 /Meta497 512 0 R /Matrix [1 0 0 1 0 0] q /Type /XObject 0.458 0 0 RG q /Font << 932 0 obj << /Subtype /Form 0 0.633 m q Q 0 w q endstream Q Q q >> Q Editor’s note No answer sheet. 0.458 0 0 RG /F1 6 0 R W* n ET 0000077108 00000 n 0.531 0 l /Matrix [1 0 0 1 0 0] BT 45.663 0 0 45.168 202.506 152.068 cm 0.283 0.366 l stream 0 G Q /BBox [0 0 9.523 0.633] Q endobj 1 g /FormType 1 /Meta504 519 0 R q q q 0 g q 0.149 0.158 TD endobj 1 J /Length 67 q /Subtype /Form -0.002 Tc /Matrix [1 0 0 1 0 0] 0 G /Meta699 Do Q 0 0.633 m 0 g 45.663 0 0 45.168 426.844 603.002 cm Q Q q >> /Meta573 588 0 R 0.458 0 0 RG Q 774 0 obj << 0 0 l /Font << -0.002 Tc /Length 55 1 g 860 0 obj << Q 9/40. 943 0 obj << /BBox [0 0 0.531 0.283] 0.564 G Q -0.002 Tc >> 0.015 w BT 0 0 l 0 0.633 m 0.458 0 0 RG q 0.458 0 0 RG Q /F1 6 0 R q q Those would all be equivalent. >> 1.547 0 l 0 G q /Matrix [1 0 0 1 0 0] 0.267 0 l /FormType 1 q 45.663 0 0 45.147 426.844 466.743 cm /F1 0.217 Tf 45.249 0 0 45.131 329.731 383.934 cm 0000198939 00000 n >> -0.002 Tc /Subtype /Form /BBox [0 0 1.547 0.633] 0.458 0 0 RG /Length 709 45.249 0 0 45.131 329.731 383.934 cm Q 45.249 0 0 45.131 441.9 152.068 cm Q 828 0 obj << BT 0.015 w /BBox [0 0 1.547 0.633] 745 0 obj << /Resources << 1 J 0 G endobj >> 0 w q 890 0 obj << >> 45.663 0 0 45.147 426.844 161.854 cm 0 g 0 0 l endstream >> /Meta577 592 0 R BT BT endobj 9.523 0.633 l q Q 0 g /Meta915 Do 9.523 0.633 l /Subtype /Form >> endstream endstream q 0.015 w 0.564 G 0 g /Subtype /Form 0 g /Meta585 600 0 R 0.015 w /Type /XObject /BBox [0 0 1.547 0.633] /Subtype /Form 0.564 G 0000202439 00000 n 0 G /Type /XObject 959 0 obj << Q 0000296099 00000 n 0 w Q 0.015 w Q Q /Type /XObject /F1 6 0 R /Meta774 Do 0.015 w 0 g 863 0 obj << /FormType 1 Q >> >> 0000178307 00000 n 0.267 0.5 l 0000086758 00000 n 0.118 0.366 m 45.663 0 0 45.147 314.675 466.743 cm 0 G 0000319761 00000 n >> 45.214 0 0 45.131 81.303 253.697 cm 0.267 0 l 11.988 0 l 1.547 0 l 0 G q >> /Matrix [1 0 0 1 0 0] /F1 0.217 Tf 0 G /BBox [0 0 1.547 0.633] 0000074183 00000 n /Meta694 Do 926 0 obj << Q 0 G 1 g 0 G /Resources << /BBox [0 0 0.263 0.5] /Type /XObject Q /F1 6 0 R Determine the sets of cakes made by the bakeshop on that particular day. -0.002 Tc 45.249 0 0 45.147 329.731 466.743 cm [(2)19(4\))] TJ /Resources << /Matrix [1 0 0 1 0 0] 0.763 0.158 TD 0.614 0.308 TD >> stream S endstream 0 0.5 m Q q /F1 6 0 R 0 G stream 0 0 l 0.417 0 l 45.249 0 0 45.131 441.9 688.823 cm /Meta931 Do Q W* n ET S stream /Resources << Q /Type /XObject 0 g /F1 6 0 R q >> 0000113894 00000 n /FormType 1 0 g /Matrix [1 0 0 1 0 0] q >> /Subtype /Form 45.249 0 0 45.131 441.9 456.957 cm Q /F1 6 0 R /BBox [0 0 1.547 0.633] [(21)] TJ 0.015 w Q /BBox [0 0 0.263 0.5] 45.249 0 0 45.131 441.9 529.98 cm 0 G 1 g endstream 1 j /Font << 15 Simplify Complex Fractions. 0000110851 00000 n >> /Meta886 Do /Meta516 Do >> Q 45.249 0 0 45.131 441.9 79.045 cm /FormType 1 0.564 G /Font << /F1 6 0 R 0000251984 00000 n /BBox [0 0 9.787 0.283] 0.015 w /Type /XObject /F1 0.217 Tf BT q /Font << /F1 0.217 Tf q S 0000301595 00000 n Q BT /BBox [0 0 0.263 0.5] /FormType 1 /Meta789 Do /Subtype /Form /Matrix [1 0 0 1 0 0] 45.249 0 0 45.131 217.562 456.957 cm /Matrix [1 0 0 1 0 0] Q 0 w q S 45.249 0 0 45.131 329.731 79.045 cm Q Multiple Choice Questions have been coming in Class 7 Fractions and Decimals exams, thus do MCQs to test understanding of important topics in the chapters. S /BBox [0 0 1.547 0.633] /Type /XObject W* n 0 g 0 g Q q 0 g 0.458 0 0 RG Q Q /Resources << /Subtype /Form 45.527 0 0 45.147 523.957 727.216 cm q BT /Meta830 Do ET 45.663 0 0 45.168 426.844 225.09 cm 1.547 0 l /Meta524 Do /Type /XObject 0.015 w ET Q Q Q 0.149 0.437 TD q /FormType 1 q /F1 0.217 Tf 0.564 G BT stream 14. /Length 8 /Subtype /Form q 1 g Q 0 0 l Q /Matrix [1 0 0 1 0 0] /F1 0.217 Tf 0 G These are NOT multiple choice they have to complete the problem and find the answer. 0.015 w 0 w /Matrix [1 0 0 1 0 0] -0.008 Tc 0.267 0.366 l -0.002 Tc 0 0.5 m >> 0 G endobj 0 g 0.417 0 l endobj ] /Matrix [1 0 0 1 0 0] 0 0.633 m 0 g Ans. 0 g /Meta746 Do Q Q endstream 1.547 0.633 l /BBox [0 0 1.547 0.633] >> /Resources << /Meta735 750 0 R q /Matrix [1 0 0 1 0 0] 762 0 obj << Q q 0 w /Length 136 0 w /FormType 1 q endstream 0.564 G 45.663 0 0 45.168 90.337 529.98 cm 0.118 0.366 m stream /Type /XObject /Meta498 Do 0 G >> 0 0.633 m /I0 52 0 R BT >> 854 0 obj << 0.031 0.087 TD /Meta512 527 0 R /Subtype /Form 0.015 w /Meta678 Do 727 0 obj << /Matrix [1 0 0 1 0 0] >> >> q /F1 0.217 Tf 1.547 0.633 l 0.381 0.366 l 0 w Q Q 45.249 0 0 45.131 329.731 529.98 cm Q Q /Matrix [1 0 0 1 0 0] Q q Q 0000028861 00000 n /Resources << q 0000201128 00000 n /F1 0.217 Tf /Matrix [1 0 0 1 0 0] 0000001900 00000 n /Meta607 Do 0 G /Meta795 Do 0 0 l endobj 0000323671 00000 n endstream /F1 6 0 R Q ET /Meta519 534 0 R [(20)] TJ Q 0.515 0.308 TD 1.547 0 l q q q 1 g 0000286036 00000 n q 0 0.308 TD 0.417 0 l 45.249 0 0 45.131 441.9 603.002 cm /Subtype /Form 45.663 0 0 45.147 90.337 612.789 cm /Meta659 Do /F1 0.217 Tf /Meta667 682 0 R /Meta663 Do /Meta481 496 0 R /BBox [0 0 9.523 0.633] /Length 55 0 G Q stream 0 g /Type /XObject endstream 0 0 l 0 g /Meta596 Do /Length 55 /Resources << 0000244270 00000 n ET BT /Matrix [1 0 0 1 0 0] BT q 0 G 0 0.283 m >> 0000245212 00000 n /Matrix [1 0 0 1 0 0] 45.214 0 0 45.131 81.303 704.632 cm W* n /Length 94 0 g 0 g These extra fractions make them a … >> 0000284811 00000 n ET Q 0000218750 00000 n Q 0 0 l /Length 55 endstream /F1 0.217 Tf 0.031 0.087 TD stream stream 0 G 0 G /Meta820 Do q /Meta944 961 0 R Q /Meta639 654 0 R 1.547 0.633 l /Matrix [1 0 0 1 0 0] 0.015 w [(10)] TJ >> 780 0 obj << Q 0 0.283 m Q /Length 55 /FormType 1 0 g 0 0 l >> /Meta680 695 0 R [(1)] TJ endobj 753 0 obj << /Matrix [1 0 0 1 0 0] ET /BBox [0 0 1.547 0.633] /Meta893 910 0 R 0000235711 00000 n -0.002 Tc 0.248 0.087 TD It is used to represent the number of parts we have out of the overall number of elements. 0.118 0.366 m q 0000248245 00000 n endobj /Meta753 768 0 R endobj 0000246030 00000 n /Meta894 Do 0.381 0.366 l /F1 6 0 R endstream [(5)] TJ 0 w 0 w Q /Matrix [1 0 0 1 0 0] Q 45.214 0 0 45.131 81.303 485.564 cm /Length 336 0000127382 00000 n /Length 51 1 g stream [(-)] TJ Q /F1 6 0 R /Meta860 Do 0 0 l 0 0.633 m 0 G 0 G /F1 6 0 R 0 G ET 0000318268 00000 n Q /Resources << ET /Length 340 Read Also: Perfect Square Trinomial Formula. /Font << 823 0 obj << /Meta633 Do 1 g 844 0 obj << /Meta579 Do Q /Type /XObject 0.118 0.366 m /F1 6 0 R /F1 6 0 R 0.531 0 l q 0.015 w /Meta496 511 0 R Q /Meta912 Do 45.214 0 0 45.131 81.303 485.564 cm >> 0.458 0 0 RG /Meta933 950 0 R 0 w endobj S -0.007 Tc q 0 0.283 m 0 g 0 0 l Q >> 0000323195 00000 n >> q q /Font << ET /F1 6 0 R q 0000110375 00000 n 0.458 0 0 RG /Meta719 Do 0.015 w q /FormType 1 /Meta710 Do 0 g Q Q ET 0 G 45.527 0 0 45.147 523.957 568.373 cm /Type /XObject /FormType 1 0 0.283 m 0 G endstream 45.249 0 0 45.131 105.393 225.09 cm 45.249 0 0 45.131 105.393 298.113 cm endobj stream /Meta931 948 0 R /Subtype /Form 812 0 obj << 0 g 0000194412 00000 n 11.988 0.283 l /F1 0.217 Tf 0 G 0 G /Subtype /Form 0000290310 00000 n 0.458 0 0 RG /FormType 1 45.226 0 0 45.147 81.303 441.148 cm stream Q 0.216 0.366 m Q /Meta927 944 0 R q Q This is the most straightforward technique for simplifying complex fractions. ET /Length 8 /Meta483 Do /Length 67 q /Meta548 Do -0.002 Tc Q >> q /Meta899 Do /Subtype /Form q 0 G Q >> 791 0 obj << /Matrix [1 0 0 1 0 0] 0000319990 00000 n 0.564 G >> /Length 51 q Q 0 G >> 874 0 obj << 0000104093 00000 n /Matrix [1 0 0 1 0 0] 0 0 l 0.047 0.087 TD endstream BT 0 w 817 0 obj << /Subtype /Form Q 0 g /Matrix [1 0 0 1 0 0] 0000047554 00000 n q Q ET 9.791 0.283 l stream 0.458 0 0 RG /Type /XObject 5.929 0.087 TD 0.665 0.158 TD BT 1.547 0 l /FormType 1 0.118 0.366 m Q /Font << /Type /XObject endstream /Matrix [1 0 0 1 0 0] ET 0.458 0 0 RG Q endobj 0000033850 00000 n /F1 6 0 R /Meta692 Do q Q 0 0.308 TD /Subtype /Form /Type /XObject /F1 6 0 R /Resources << 0.267 0.5 l 0000074903 00000 n Q 0 g Q /Subtype /Form q q 0 g q [(C\))] TJ /FormType 1 0000253218 00000 n endstream 0.458 0 0 RG endstream BT 0 0 l endstream /FormType 1 endstream 0000221599 00000 n Q 0.267 0.5 l PDAs stands for_____. Q /Meta715 Do q trailer /BBox [0 0 9.523 0.633] 761 0 obj << Select a problem set using the buttons above, then use your mouse or tab key to select a question. /Meta706 Do 0 G stream 0 0 l /Meta840 857 0 R >> /Meta576 Do /Meta721 736 0 R 0000214187 00000 n Q >> 0000039311 00000 n 45.249 0 0 45.131 217.562 603.002 cm /Meta797 Do [(7)] TJ /Meta930 947 0 R W* n /Subtype /Form 45.663 0 0 45.168 314.675 603.002 cm Q q /Subtype /Form Q Q 0000055417 00000 n Q 969 0 obj << 0 g q 0000114380 00000 n 45.663 0 0 45.168 202.506 688.823 cm Q Thus, you know: Now, simplify this to: or Now, remember that when you divide fractions, you multiply the numerator by the reciprocal of the denominator: /BBox [0 0 1.547 0.633] q 0 G 0 w q 0000041050 00000 n /Length 51 /BBox [0 0 0.263 0.5] /FormType 1 0 g /Type /XObject 0 G endstream q 45.249 0 0 45.131 441.9 456.957 cm 0000194168 00000 n q /Subtype /Form Q Q 1 g 0.564 G 0.267 0.5 l /Meta540 Do Q 0.458 0 0 RG /FormType 1 stream q /BBox [0 0 1.547 0.633] q [(7)] TJ 0 w 9.791 0.283 l >> 0.458 0 0 RG 0000229849 00000 n 0 G /BBox [0 0 0.413 0.283] 0.381 0.366 l 0000231413 00000 n 0000180242 00000 n 1.547 0.633 l 0000302314 00000 n 0 0 l q ET 0 0.366 m 0 G 0.458 0 0 RG [(9)] TJ /FormType 1 /FormType 1 /Type /XObject /Subtype /Form 0.564 G q 0.458 0 0 RG /Meta503 518 0 R /Type /XObject endobj 0 0 l 0 0.087 TD >> q 45.324 0 0 45.147 54.202 727.216 cm 963 0 obj << 738 0 obj << 0.015 w /Subtype /Form 45.214 0 0 45.131 81.303 558.586 cm 0 g q 0.267 0 l /Resources << /Meta687 702 0 R Q /BBox [0 0 9.523 0.633] q q /Matrix [1 0 0 1 0 0] >> 45.214 0 0 45.131 81.303 107.652 cm Q stream 45.214 0 0 45.131 81.303 631.609 cm ET 0.267 0 l 0.614 0.308 TD 0000190822 00000 n q 45.249 0 0 45.131 329.731 676.025 cm 826 0 obj << 0 0.633 m /Meta879 896 0 R /Resources << /Subtype /Form /Type /XObject 0.458 0 0 RG q endstream q W* n 0 0.283 m 0000001632 00000 n q 0.149 0.158 TD >> 0000318510 00000 n /Meta618 633 0 R q /Type /XObject q 0.458 0 0 RG /F1 6 0 R /Meta561 Do 0.458 0 0 RG q 1 g /Meta781 796 0 R 0.417 0 l /Meta521 Do BT endobj 0.417 0.283 l 0.015 w BT 45.324 0 0 45.147 54.202 190.461 cm q 733 0 obj << 0000289126 00000 n /Meta805 822 0 R 0 G endstream 0000027707 00000 n /Meta808 825 0 R /Subtype /Form 0000034599 00000 n 749 0 obj << 0 g 0 G q Q /Meta649 Do 0 0 l /Length 136 0.458 0 0 RG 0.458 0 0 RG /Subtype /Form ET /Meta604 Do 0 0 l Q >> /Subtype /Form /Matrix [1 0 0 1 0 0] q Q BT /Meta880 897 0 R >> 0 0.308 TD 778 0 obj << 0000192030 00000 n 0 g endobj endstream ET q /Type /XObject 0 0.5 m Q 0000220976 00000 n Q /BBox [0 0 0.263 0.283] Q 0000115099 00000 n 0.149 0.437 TD q 1 g >> q 0.248 0.087 TD q /Meta600 615 0 R 0.564 G 45.214 0 0 45.131 81.303 485.564 cm 0 0.633 m 0.267 0.5 l Q ET 1. 0000125671 00000 n q 0000052216 00000 n W* n Q /Type /XObject 45.214 0 0 45.131 81.303 558.586 cm BT /FormType 1 >> q 0000229003 00000 n 0 0 l 0.047 0.087 TD Q /Meta588 603 0 R stream 0000200176 00000 n /Matrix [1 0 0 1 0 0] /Meta952 969 0 R /Subtype /Form 45.214 0 0 45.131 81.303 412.541 cm 0000012297 00000 n endobj >> /Type /XObject endstream /Type /XObject Q 0 0.633 m 0000229469 00000 n 45.249 0 0 45.131 105.393 456.957 cm q 0.458 0 0 RG /Meta697 712 0 R q /Meta577 Do Q /Subtype /Form /Length 66 825 0 obj << >> 0.564 G /F1 6 0 R 0.564 G [(5)] TJ /BBox [0 0 0.263 0.283] /Meta508 Do 1 g BT ET q 0000321483 00000 n >> 0000171349 00000 n 0 0 l stream 736 0 obj << /Subtype /Form /Meta486 501 0 R stream 0000142332 00000 n W* n 0 w endstream 1 J Q /Meta817 Do Q q 0.015 w q W* n /Type /XObject /Type /XObject q /F1 6 0 R 0 0.283 m /Resources << 0000188025 00000 n Q q /BBox [0 0 9.523 0.633] /Meta844 861 0 R /Type /XObject 0 0.5 m q 45.214 0 0 45.131 81.303 631.609 cm /FormType 1 /Meta591 606 0 R 0000114137 00000 n /FormType 1 /Meta889 906 0 R endstream 45.226 0 0 45.147 81.303 673.014 cm 0 g /Meta817 834 0 R 0 0.633 m 0.564 G 0000190208 00000 n 0 G endobj stream 760 0 obj << -0.002 Tc >> 0.458 0 0 RG /Meta714 Do stream Q /Meta724 739 0 R stream 0.015 w 0.564 G q 0 0.283 m ET 0 G 0 G q /Meta546 Do >> 0 0.5 m q Q 0000226140 00000 n S 1 g /BBox [0 0 1.547 0.633] /Meta499 Do 0.564 G /Font << Q 0.015 w /Matrix [1 0 0 1 0 0] /Subtype /Form 0.458 0 0 RG /Type /XObject If the bakeshop used 1/2 of a bag of cooking flour on that particular day. >> 0 g 0000221832 00000 n 0 0 l /F1 6 0 R /Subtype /Form /Matrix [1 0 0 1 0 0] /F1 0.217 Tf 0 g 1 g Q /Meta714 729 0 R 0 0 l Q 0000198092 00000 n 0000170970 00000 n /Length 66 Q Q 0.381 0.366 l 0 G /Meta688 Do Q W* n q q 0 w /Length 66 0000171203 00000 n 0 0.5 m 45.527 0 0 45.147 523.957 336.507 cm >> /Meta600 Do 0000240981 00000 n 0 0.283 m Q 0000018202 00000 n q 0000296332 00000 n /Meta606 621 0 R q 0 0 l 0.458 0 0 RG /Meta774 789 0 R 0000203639 00000 n 45.663 0 0 45.168 314.675 456.957 cm 0000035086 00000 n 0 w W* n 0 w /F1 6 0 R /Length 54 300 seconds . stream 0000144617 00000 n /Length 385 0.458 0 0 RG /Matrix [1 0 0 1 0 0] 1.547 0 l q /Subtype /Form /F1 6 0 R W* n /FormType 1 /Resources << stream 0.015 w 0 0.5 m W* n /F1 0.217 Tf Q >> Q >> 740 0 obj << endstream /Length 340 0000147961 00000 n endstream 0 g q q 0000258988 00000 n /Subtype /Form /Length 55 0.267 0 l q 45.663 0 0 45.147 426.844 685.812 cm 0.015 w /Matrix [1 0 0 1 0 0] 0 0.087 TD q (3/4)/(9/10) is another facility fraction with 3/4 as the numerator and also 9/10 as the. 0.015 w 1 g /Length 62 Q q Q q 964 0 obj << 0.564 G BT 0 G 0 g Q endstream endstream endstream 0000079052 00000 n /Meta832 Do q 0 g Q q 901 0 obj << 45.663 0 0 45.168 202.506 529.98 cm /Resources << 0.015 w 0 G 0.248 0.087 TD An embedded system with answers are presented strengthen concepts and improve marks in tests and exams with multiplication the of. 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